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-6p^2+2p+60=0
a = -6; b = 2; c = +60;
Δ = b2-4ac
Δ = 22-4·(-6)·60
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1444}=38$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-38}{2*-6}=\frac{-40}{-12} =3+1/3 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+38}{2*-6}=\frac{36}{-12} =-3 $
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